132301221443333 has 4 divisors (see below), whose sum is σ = 132304837947168. Its totient is φ = 132297604939500.

The previous prime is 132301221443299. The next prime is 132301221443353. The reversal of 132301221443333 is 333344122103231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132301221443333 - 2¹⁰ = 132301221442309 is a prime.

It is a super-2 number, since 2×132301221443333² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132301221443293 and 132301221443302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132301221443353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1808197043 + ... + 1808270208.

It is an arithmetic number, because the mean of its divisors is an integer number (33076209486792).

Almost surely, 2^{132301221443333} is an apocalyptic number.

It is an amenable number.

132301221443333 is a deficient number, since it is larger than the sum of its proper divisors (3616503835).

132301221443333 is an equidigital number, since it uses as much as digits as its factorization.

132301221443333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3616503834.

The product of its (nonzero) digits is 93312, while the sum is 35.

Adding to 132301221443333 its reverse (333344122103231), we get a palindrome (465645343546564).

The spelling of 132301221443333 in words is "one hundred thirty-two trillion, three hundred one billion, two hundred twenty-one million, four hundred forty-three thousand, three hundred thirty-three".