Base | Representation |
---|---|
bin | 1100000010000110000101… |
… | …0001101100011100010001 |
3 | 1201211210021121010212001011 |
4 | 3000201201101230130101 |
5 | 3213230302103100423 |
6 | 44045501033010521 |
7 | 2533562662361410 |
oct | 300414121543421 |
9 | 51753247125034 |
10 | 13230131300113 |
11 | 424095a234712 |
12 | 1598108253a41 |
13 | 74c799621b50 |
14 | 33a4adb6d477 |
15 | 17e22d01db0d |
hex | c086146c711 |
13230131300113 has 32 divisors (see below), whose sum is σ = 16340891164416. Its totient is φ = 10430742912768.
The previous prime is 13230131300081. The next prime is 13230131300123. The reversal of 13230131300113 is 31100313103231.
It is a cyclic number.
It is not a de Polignac number, because 13230131300113 - 25 = 13230131300081 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13230131300123) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 245352631 + ... + 245406547.
It is an arithmetic number, because the mean of its divisors is an integer number (510652848888).
Almost surely, 213230131300113 is an apocalyptic number.
13230131300113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
13230131300113 is a deficient number, since it is larger than the sum of its proper divisors (3110759864303).
13230131300113 is a wasteful number, since it uses less digits than its factorization.
13230131300113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63433.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 13230131300113 its reverse (31100313103231), we get a palindrome (44330444403344).
The spelling of 13230131300113 in words is "thirteen trillion, two hundred thirty billion, one hundred thirty-one million, three hundred thousand, one hundred thirteen".
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