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132303233113 = 679119482143
BaseRepresentation
bin111101100110111100…
…0110010000001011001
3110122111102212121110221
41323031320302001121
54131424111424423
6140440153240041
712362411632462
oct1731570620131
9418442777427
10132303233113
11511227a9277
1221784103021
13c62610c46c
146591339d69
153695172e5d
hex1ecde32059

132303233113 has 4 divisors (see below), whose sum is σ = 132322722048. Its totient is φ = 132283744180.

The previous prime is 132303233093. The next prime is 132303233147. The reversal of 132303233113 is 311332303231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132303233113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132303233213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9734281 + ... + 9747862.

It is an arithmetic number, because the mean of its divisors is an integer number (33080680512).

Almost surely, 2132303233113 is an apocalyptic number.

It is an amenable number.

132303233113 is a deficient number, since it is larger than the sum of its proper divisors (19488935).

132303233113 is an equidigital number, since it uses as much as digits as its factorization.

132303233113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19488934.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 132303233113 its reverse (311332303231), we get a palindrome (443635536344).

The spelling of 132303233113 in words is "one hundred thirty-two billion, three hundred three million, two hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 6791 19482143 132303233113