Base | Representation |
---|---|
bin | 1100000010000111000111… |
… | …1110010110010001100111 |
3 | 1201211211000010021111110000 |
4 | 3000201301332112101213 |
5 | 3213231340312110010 |
6 | 44045544521232343 |
7 | 2533602633500421 |
oct | 300416176262147 |
9 | 51754003244400 |
10 | 13230411441255 |
11 | 4240a93384918 |
12 | 15981860326b3 |
13 | 74c812688838 |
14 | 33a4d9053811 |
15 | 17e2479087c0 |
hex | c0871f96467 |
13230411441255 has 80 divisors (see below), whose sum is σ = 24005246325984. Its totient is φ = 6970401734400.
The previous prime is 13230411441229. The next prime is 13230411441271. The reversal of 13230411441255 is 55214411403231.
13230411441255 is a `hidden beast` number, since 1 + 3 + 230 + 4 + 1 + 1 + 4 + 412 + 5 + 5 = 666.
It is not a de Polignac number, because 13230411441255 - 25 = 13230411441223 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 393312297 + ... + 393345933.
Almost surely, 213230411441255 is an apocalyptic number.
13230411441255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13230411441255 is a deficient number, since it is larger than the sum of its proper divisors (10774834884729).
13230411441255 is a wasteful number, since it uses less digits than its factorization.
13230411441255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45438 (or 45429 counting only the distinct ones).
The product of its (nonzero) digits is 57600, while the sum is 36.
Adding to 13230411441255 its reverse (55214411403231), we get a palindrome (68444822844486).
The spelling of 13230411441255 in words is "thirteen trillion, two hundred thirty billion, four hundred eleven million, four hundred forty-one thousand, two hundred fifty-five".
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