13230622014333 has 4 divisors (see below), whose sum is σ = 17640829352448. Its totient is φ = 8820414676220.

The previous prime is 13230622014299. The next prime is 13230622014343. The reversal of 13230622014333 is 33341022603231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13230622014333 - 2¹⁸ = 13230621752189 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13230622014294 and 13230622014303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13230622014343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2205103669053 + ... + 2205103669058.

It is an arithmetic number, because the mean of its divisors is an integer number (4410207338112).

Almost surely, 2^{13230622014333} is an apocalyptic number.

It is an amenable number.

13230622014333 is a deficient number, since it is larger than the sum of its proper divisors (4410207338115).

13230622014333 is an equidigital number, since it uses as much as digits as its factorization.

13230622014333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4410207338114.

The product of its (nonzero) digits is 46656, while the sum is 33.

Adding to 13230622014333 its reverse (33341022603231), we get a palindrome (46571644617564).

The spelling of 13230622014333 in words is "thirteen trillion, two hundred thirty billion, six hundred twenty-two million, fourteen thousand, three hundred thirty-three".