Base | Representation |
---|---|
bin | 111101100111001011… |
… | …0111010000011010011 |
3 | 110122111222201211102012 |
4 | 1323032112322003103 |
5 | 4131433122132243 |
6 | 140441034413135 |
7 | 12362536023431 |
oct | 1731626720323 |
9 | 418458654365 |
10 | 132311130323 |
11 | 51127202599 |
12 | 217868911ab |
13 | c627945b78 |
14 | 65923d3d51 |
15 | 3695bd2d18 |
hex | 1ece5ba0d3 |
132311130323 has 4 divisors (see below), whose sum is σ = 132322560840. Its totient is φ = 132299699808.
The previous prime is 132311130293. The next prime is 132311130331. The reversal of 132311130323 is 323031113231.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 323031113231 = 293 ⋅1102495267.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132311130323 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132311130223) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5697878 + ... + 5721051.
It is an arithmetic number, because the mean of its divisors is an integer number (33080640210).
Almost surely, 2132311130323 is an apocalyptic number.
132311130323 is a deficient number, since it is larger than the sum of its proper divisors (11430517).
132311130323 is a wasteful number, since it uses less digits than its factorization.
132311130323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11430516.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 132311130323 its reverse (323031113231), we get a palindrome (455342243554).
The spelling of 132311130323 in words is "one hundred thirty-two billion, three hundred eleven million, one hundred thirty thousand, three hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.119 sec. • engine limits •