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13231142115403 = 22403695905787
BaseRepresentation
bin1100000010001001110110…
…0001101001100001001011
31201211212220001011120221111
43000202131201221201023
53213234334340143103
644050145222151151
72533630015225642
oct300423541514113
951755801146844
1013231142115403
114241328875153
12159834a8824b7
1374c8cab779c4
1433a5680d4359
1517e28bb3986d
hexc089d86984b

13231142115403 has 4 divisors (see below), whose sum is σ = 13231150261560. Its totient is φ = 13231133969248.

The previous prime is 13231142115337. The next prime is 13231142115419. The reversal of 13231142115403 is 30451124113231.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13231142115403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13231142155403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 712525 + ... + 5193262.

It is an arithmetic number, because the mean of its divisors is an integer number (3307787565390).

Almost surely, 213231142115403 is an apocalyptic number.

13231142115403 is a deficient number, since it is larger than the sum of its proper divisors (8146157).

13231142115403 is an equidigital number, since it uses as much as digits as its factorization.

13231142115403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8146156.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 13231142115403 its reverse (30451124113231), we get a palindrome (43682266228634).

The spelling of 13231142115403 in words is "thirteen trillion, two hundred thirty-one billion, one hundred forty-two million, one hundred fifteen thousand, four hundred three".

Divisors: 1 2240369 5905787 13231142115403