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1323130015 = 5264626003
BaseRepresentation
bin100111011011101…
…0101110010011111
310102012200222011101
41032313111302133
510202210130030
6335143133531
744534263624
oct11667256237
93365628141
101323130015
11619966189
1230b1442a7
13181175c8c
14c7a2234b
157b25d7ca
hex4edd5c9f

1323130015 has 4 divisors (see below), whose sum is σ = 1587756024. Its totient is φ = 1058504008.

The previous prime is 1323129979. The next prime is 1323130049. The reversal of 1323130015 is 5100313231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1323130015 - 29 = 1323129503 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1323129974 and 1323130001.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132312997 + ... + 132313006.

It is an arithmetic number, because the mean of its divisors is an integer number (396939006).

Almost surely, 21323130015 is an apocalyptic number.

1323130015 is a deficient number, since it is larger than the sum of its proper divisors (264626009).

1323130015 is an equidigital number, since it uses as much as digits as its factorization.

1323130015 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 264626008.

The product of its (nonzero) digits is 270, while the sum is 19.

The square root of 1323130015 is about 36374.8541577832. The cubic root of 1323130015 is about 1097.8276728745.

Adding to 1323130015 its reverse (5100313231), we get a palindrome (6423443246).

The spelling of 1323130015 in words is "one billion, three hundred twenty-three million, one hundred thirty thousand, fifteen".

Divisors: 1 5 264626003 1323130015