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1323140000101 = 3881833408547
BaseRepresentation
bin10011010000010001010…
…010100010100101100101
311200111020220100020211221
4103100101102202211211
5133134242320000401
62451501522100341
7164410433301463
oct23202122424545
94614226306757
101323140000101
11470160043817
12194524aaa6b1
1397a051939aa
144807c8bb833
152464068b7a1
hex134114a2965

1323140000101 has 4 divisors (see below), whose sum is σ = 1323143796832. Its totient is φ = 1323136203372.

The previous prime is 1323140000081. The next prime is 1323140000129. The reversal of 1323140000101 is 1010000413231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1323140000101 - 25 = 1323140000069 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1323140004101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1316091 + ... + 2092456.

It is an arithmetic number, because the mean of its divisors is an integer number (330785949208).

Almost surely, 21323140000101 is an apocalyptic number.

It is an amenable number.

1323140000101 is a deficient number, since it is larger than the sum of its proper divisors (3796731).

1323140000101 is an equidigital number, since it uses as much as digits as its factorization.

1323140000101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3796730.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1323140000101 its reverse (1010000413231), we get a palindrome (2333140413332).

The spelling of 1323140000101 in words is "one trillion, three hundred twenty-three billion, one hundred forty million, one hundred one", and thus it is an aban number.

Divisors: 1 388183 3408547 1323140000101