Base | Representation |
---|---|
bin | 10011010000010001011… |
… | …010010000001101110010 |
3 | 11200111021001010222101011 |
4 | 103100101122100031302 |
5 | 133134243324201002 |
6 | 2451502033301134 |
7 | 164410456422313 |
oct | 23202132201562 |
9 | 4614231128334 |
10 | 1323142022002 |
11 | 4701611a4909 |
12 | 1945257047aa |
13 | 97a05721098 |
14 | 4807cc8660a |
15 | 2464093a8d7 |
hex | 13411690372 |
1323142022002 has 4 divisors (see below), whose sum is σ = 1984713033006. Its totient is φ = 661571011000.
The previous prime is 1323142021969. The next prime is 1323142022107. The reversal of 1323142022002 is 2002202413231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1300920455241 + 22221566761 = 1140579^2 + 149069^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 330785505499 + ... + 330785505502.
Almost surely, 21323142022002 is an apocalyptic number.
1323142022002 is a deficient number, since it is larger than the sum of its proper divisors (661571011004).
1323142022002 is an equidigital number, since it uses as much as digits as its factorization.
1323142022002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 661571011003.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 1323142022002 its reverse (2002202413231), we get a palindrome (3325344435233).
The spelling of 1323142022002 in words is "one trillion, three hundred twenty-three billion, one hundred forty-two million, twenty-two thousand, two".
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