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132314525151 = 3346912713993
BaseRepresentation
bin111101100111010001…
…1110110110111011111
3110122112020010022020120
41323032203312313133
54131440004301101
6140441235250023
712362606623044
oct1731643666737
9418466108216
10132314525151
1151129111136
1221787a49913
13c628564143
146592a391cb
153696153b36
hex1ece8f6ddf

132314525151 has 8 divisors (see below), whose sum is σ = 176470236720. Its totient is φ = 88184248512.

The previous prime is 132314525149. The next prime is 132314525173. The reversal of 132314525151 is 151525413231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 132314525151 - 21 = 132314525149 is a prime.

It is a super-2 number, since 2×1323145251512 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132314525191) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6346590 + ... + 6367403.

It is an arithmetic number, because the mean of its divisors is an integer number (22058779590).

Almost surely, 2132314525151 is an apocalyptic number.

132314525151 is a deficient number, since it is larger than the sum of its proper divisors (44155711569).

132314525151 is a wasteful number, since it uses less digits than its factorization.

132314525151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12717465.

The product of its digits is 18000, while the sum is 33.

Adding to 132314525151 its reverse (151525413231), we get a palindrome (283839938382).

The spelling of 132314525151 in words is "one hundred thirty-two billion, three hundred fourteen million, five hundred twenty-five thousand, one hundred fifty-one".

Divisors: 1 3 3469 10407 12713993 38141979 44104841717 132314525151