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132320143 = 601122013
BaseRepresentation
bin1111110001100…
…00101110001111
3100012222120010001
413320300232033
5232333221033
621044025131
73164463004
oct770605617
9305876101
10132320143
116876709a
12383921a7
132154b857
14138058ab
15b93ae7d
hex7e30b8f

132320143 has 4 divisors (see below), whose sum is σ = 132348168. Its totient is φ = 132292120.

The previous prime is 132320141. The next prime is 132320179. The reversal of 132320143 is 341023231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132320143 - 21 = 132320141 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 132320143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132320141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4996 + ... + 17017.

It is an arithmetic number, because the mean of its divisors is an integer number (33087042).

Almost surely, 2132320143 is an apocalyptic number.

132320143 is a deficient number, since it is larger than the sum of its proper divisors (28025).

132320143 is an equidigital number, since it uses as much as digits as its factorization.

132320143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28024.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 132320143 is about 11503.0492913836. The cubic root of 132320143 is about 509.5756344286.

Adding to 132320143 its reverse (341023231), we get a palindrome (473343374).

The spelling of 132320143 in words is "one hundred thirty-two million, three hundred twenty thousand, one hundred forty-three".

Divisors: 1 6011 22013 132320143