13232101312021 has 4 divisors (see below), whose sum is σ = 13232755771200. Its totient is φ = 13231446852844.

The previous prime is 13232101312013. The next prime is 13232101312039. The reversal of 13232101312021 is 12021310123231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13232101312021 - 2³ = 13232101312013 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13232101311983 and 13232101312001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13232101312051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 327199261 + ... + 327239698.

It is an arithmetic number, because the mean of its divisors is an integer number (3308188942800).

Almost surely, 2^{13232101312021} is an apocalyptic number.

It is an amenable number.

13232101312021 is a deficient number, since it is larger than the sum of its proper divisors (654459179).

13232101312021 is an equidigital number, since it uses as much as digits as its factorization.

13232101312021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 654459178.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 13232101312021 its reverse (12021310123231), we get a palindrome (25253411435252).

The spelling of 13232101312021 in words is "thirteen trillion, two hundred thirty-two billion, one hundred one million, three hundred twelve thousand, twenty-one".