13232105641255 has 4 divisors (see below), whose sum is σ = 15878526769512. Its totient is φ = 10585684513000.

The previous prime is 13232105641231. The next prime is 13232105641297. The reversal of 13232105641255 is 55214650123231.

13232105641255 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13232105641255 - 2¹³ = 13232105633063 is a prime.

It is a super-3 number, since 3×13232105641255³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1323210564121 + ... + 1323210564130.

It is an arithmetic number, because the mean of its divisors is an integer number (3969631692378).

Almost surely, 2^{13232105641255} is an apocalyptic number.

13232105641255 is a deficient number, since it is larger than the sum of its proper divisors (2646421128257).

13232105641255 is an equidigital number, since it uses as much as digits as its factorization.

13232105641255 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2646421128256.

The product of its (nonzero) digits is 216000, while the sum is 40.

Adding to 13232105641255 its reverse (55214650123231), we get a palindrome (68446755764486).

The spelling of 13232105641255 in words is "thirteen trillion, two hundred thirty-two billion, one hundred five million, six hundred forty-one thousand, two hundred fifty-five".