1323211102441 has 4 divisors (see below), whose sum is σ = 1365895331584. Its totient is φ = 1280526873300.

The previous prime is 1323211102391. The next prime is 1323211102463. The reversal of 1323211102441 is 1442011123231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1323211102441 - 2¹⁹ = 1323210578153 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1323211102471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21342114525 + ... + 21342114586.

It is an arithmetic number, because the mean of its divisors is an integer number (341473832896).

Almost surely, 2^{1323211102441} is an apocalyptic number.

It is an amenable number.

1323211102441 is a deficient number, since it is larger than the sum of its proper divisors (42684229143).

1323211102441 is an equidigital number, since it uses as much as digits as its factorization.

1323211102441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42684229142.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1323211102441 its reverse (1442011123231), we get a palindrome (2765222225672).

The spelling of 1323211102441 in words is "one trillion, three hundred twenty-three billion, two hundred eleven million, one hundred two thousand, four hundred forty-one".