Base | Representation |
---|---|
bin | 10011010000010110101… |
… | …110111001100000101111 |
3 | 11200111111021011210100112 |
4 | 103100112232321200233 |
5 | 133134434204220421 |
6 | 2451514543250235 |
7 | 164412622432541 |
oct | 23202656714057 |
9 | 4614437153315 |
10 | 1323231320111 |
11 | 4701a76468a8 |
12 | 19454b5a997b |
13 | 97a1b0886bc |
14 | 4808aa8d691 |
15 | 246486c945b |
hex | 13416bb982f |
1323231320111 has 4 divisors (see below), whose sum is σ = 1323241237032. Its totient is φ = 1323221403192.
The previous prime is 1323231320101. The next prime is 1323231320197. The reversal of 1323231320111 is 1110231323231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1323231320111 - 226 = 1323164211247 is a prime.
It is a super-2 number, since 2×13232313201112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1323231320101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4755545 + ... + 5026098.
It is an arithmetic number, because the mean of its divisors is an integer number (330810309258).
Almost surely, 21323231320111 is an apocalyptic number.
1323231320111 is a deficient number, since it is larger than the sum of its proper divisors (9916921).
1323231320111 is an equidigital number, since it uses as much as digits as its factorization.
1323231320111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9916920.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1323231320111 its reverse (1110231323231), we get a palindrome (2433462643342).
The spelling of 1323231320111 in words is "one trillion, three hundred twenty-three billion, two hundred thirty-one million, three hundred twenty thousand, one hundred eleven".
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