Base | Representation |
---|---|
bin | 111101100111100100… |
… | …0011011110000011001 |
3 | 110122112220011102220010 |
4 | 1323033020123300121 |
5 | 4131444433112213 |
6 | 140442220552133 |
7 | 12363054256161 |
oct | 1731710336031 |
9 | 418486142803 |
10 | 132324113433 |
11 | 5113356aa36 |
12 | 2178b0b2649 |
13 | c62a540495 |
14 | 65940135a1 |
15 | 3696de9ac3 |
hex | 1ecf21bc19 |
132324113433 has 8 divisors (see below), whose sum is σ = 176455027168. Its totient is φ = 88204637664.
The previous prime is 132324113401. The next prime is 132324113447. The reversal of 132324113433 is 334311423231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 132324113433 - 25 = 132324113401 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 132324113433.
It is not an unprimeable number, because it can be changed into a prime (132324113473) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2832460 + ... + 2878797.
It is an arithmetic number, because the mean of its divisors is an integer number (22056878396).
Almost surely, 2132324113433 is an apocalyptic number.
It is an amenable number.
132324113433 is a deficient number, since it is larger than the sum of its proper divisors (44130913735).
132324113433 is an equidigital number, since it uses as much as digits as its factorization.
132324113433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5718983.
The product of its digits is 15552, while the sum is 30.
Adding to 132324113433 its reverse (334311423231), we get a palindrome (466635536664).
The spelling of 132324113433 in words is "one hundred thirty-two billion, three hundred twenty-four million, one hundred thirteen thousand, four hundred thirty-three".
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