Base | Representation |
---|---|
bin | 11110000101101010111110… |
… | …001111011100110100011001 |
3 | 122100112201210021002212200021 |
4 | 132011222332033130310121 |
5 | 114321103130313023001 |
6 | 1145240030032110441 |
7 | 36605415602544130 |
oct | 3605527617346431 |
9 | 570481707085607 |
10 | 132331134111001 |
11 | 3918a356381761 |
12 | 12a127b1095421 |
13 | 58aba06c75137 |
14 | 2496c0aa96917 |
15 | 10473831d1ba1 |
hex | 785abe3dcd19 |
132331134111001 has 8 divisors (see below), whose sum is σ = 151235661847424. Its totient is φ = 113426626376160.
The previous prime is 132331134110957. The next prime is 132331134111023. The reversal of 132331134111001 is 100111431133231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132331134111001 - 241 = 130132110855449 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132331134111031) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13979716 + ... + 21449818.
It is an arithmetic number, because the mean of its divisors is an integer number (18904457730928).
Almost surely, 2132331134111001 is an apocalyptic number.
It is an amenable number.
132331134111001 is a deficient number, since it is larger than the sum of its proper divisors (18904527736423).
132331134111001 is an equidigital number, since it uses as much as digits as its factorization.
132331134111001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10000791.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 132331134111001 its reverse (100111431133231), we get a palindrome (232442565244232).
The spelling of 132331134111001 in words is "one hundred thirty-two trillion, three hundred thirty-one billion, one hundred thirty-four million, one hundred eleven thousand, one".
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