1323314402433 has 4 divisors (see below), whose sum is σ = 1764419203248. Its totient is φ = 882209601620.

The previous prime is 1323314402413. The next prime is 1323314402467. The reversal of 1323314402433 is 3342044133231.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1323314402433 - 2³⁸ = 1048436495489 is a prime.

It is a super-2 number, since 2×1323314402433² (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1323314402394 and 1323314402403.

It is not an unprimeable number, because it can be changed into a prime (1323314402413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220552400403 + ... + 220552400408.

It is an arithmetic number, because the mean of its divisors is an integer number (441104800812).

Almost surely, 2^{1323314402433} is an apocalyptic number.

It is an amenable number.

1323314402433 is a deficient number, since it is larger than the sum of its proper divisors (441104800815).

1323314402433 is an equidigital number, since it uses as much as digits as its factorization.

1323314402433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 441104800814.

The product of its (nonzero) digits is 62208, while the sum is 33.

Adding to 1323314402433 its reverse (3342044133231), we get a palindrome (4665358535664).

The spelling of 1323314402433 in words is "one trillion, three hundred twenty-three billion, three hundred fourteen million, four hundred two thousand, four hundred thirty-three".