Search a number
-
+
13233201103 = 61216937723
BaseRepresentation
bin11000101001100001…
…01001111111001111
31021011020121021020101
430110300221333033
5204100144413403
610025041231531
7645634232143
oct142460517717
937136537211
1013233201103
115680884941
1226939325a7
13132b7b2015
148d7711223
15526b6871d
hex314c29fcf

13233201103 has 4 divisors (see below), whose sum is σ = 13450138888. Its totient is φ = 13016263320.

The previous prime is 13233201089. The next prime is 13233201131. The reversal of 13233201103 is 30110233231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13233201103 is a prime.

It is a super-2 number, since 2×132332011032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13233201403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 108468801 + ... + 108468922.

It is an arithmetic number, because the mean of its divisors is an integer number (3362534722).

Almost surely, 213233201103 is an apocalyptic number.

13233201103 is a deficient number, since it is larger than the sum of its proper divisors (216937785).

13233201103 is an equidigital number, since it uses as much as digits as its factorization.

13233201103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 216937784.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 13233201103 its reverse (30110233231), we get a palindrome (43343434334).

The spelling of 13233201103 in words is "thirteen billion, two hundred thirty-three million, two hundred one thousand, one hundred three".

Divisors: 1 61 216937723 13233201103