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132333020451143 = 803916461378337
BaseRepresentation
bin11110000101101100101110…
…101011010001000101000111
3122100112220122201120212212222
4132011230232223101011013
5114321121011213414033
61145240541135002555
736605513416302101
oct3605545653210507
9570486581525788
10132333020451143
1139190134147a56
1212a1303896945b
1358abc47a05335
142496d49406571
151047443ae2598
hex785b2ead1147

132333020451143 has 4 divisors (see below), whose sum is σ = 132349481837520. Its totient is φ = 132316559064768.

The previous prime is 132333020451019. The next prime is 132333020451173. The reversal of 132333020451143 is 341154020333231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132333020451143 - 210 = 132333020450119 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132333020451173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8230681130 + ... + 8230697207.

It is an arithmetic number, because the mean of its divisors is an integer number (33087370459380).

Almost surely, 2132333020451143 is an apocalyptic number.

132333020451143 is a deficient number, since it is larger than the sum of its proper divisors (16461386377).

132333020451143 is an equidigital number, since it uses as much as digits as its factorization.

132333020451143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16461386376.

The product of its (nonzero) digits is 77760, while the sum is 35.

Adding to 132333020451143 its reverse (341154020333231), we get a palindrome (473487040784374).

The spelling of 132333020451143 in words is "one hundred thirty-two trillion, three hundred thirty-three billion, twenty million, four hundred fifty-one thousand, one hundred forty-three".

Divisors: 1 8039 16461378337 132333020451143