1323401200133 has 4 divisors (see below), whose sum is σ = 1342040653728. Its totient is φ = 1304761746540.

The previous prime is 1323401200129. The next prime is 1323401200153. The reversal of 1323401200133 is 3310021043231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1323401200133 - 2² = 1323401200129 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1323401200099 and 1323401200108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1323401200153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9319726691 + ... + 9319726832.

It is an arithmetic number, because the mean of its divisors is an integer number (335510163432).

Almost surely, 2^{1323401200133} is an apocalyptic number.

It is an amenable number.

1323401200133 is a deficient number, since it is larger than the sum of its proper divisors (18639453595).

1323401200133 is an equidigital number, since it uses as much as digits as its factorization.

1323401200133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18639453594.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 1323401200133 its reverse (3310021043231), we get a palindrome (4633422243364).

The spelling of 1323401200133 in words is "one trillion, three hundred twenty-three billion, four hundred one million, two hundred thousand, one hundred thirty-three".