Base | Representation |
---|---|
bin | 1100000010010100110111… |
… | …0101111110011100110001 |
3 | 1201212011112012101120211202 |
4 | 3000211031311332130301 |
5 | 3213311414124442113 |
6 | 44051354533020545 |
7 | 2534063224636340 |
oct | 300451565763461 |
9 | 51764465346752 |
10 | 13234100234033 |
11 | 424260662a498 |
12 | 1598a35484755 |
13 | 74cc7c987263 |
14 | 33a768d17b57 |
15 | 17e3b16a9258 |
hex | c094dd7e731 |
13234100234033 has 16 divisors (see below), whose sum is σ = 15567221967360. Its totient is φ = 11016320328000.
The previous prime is 13234100234029. The next prime is 13234100234063. The reversal of 13234100234033 is 33043200143231.
It is a cyclic number.
It is not a de Polignac number, because 13234100234033 - 22 = 13234100234029 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13234100233987 and 13234100234005.
It is not an unprimeable number, because it can be changed into a prime (13234100234063) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 196125818 + ... + 196193283.
It is an arithmetic number, because the mean of its divisors is an integer number (972951372960).
Almost surely, 213234100234033 is an apocalyptic number.
It is an amenable number.
13234100234033 is a deficient number, since it is larger than the sum of its proper divisors (2333121733327).
13234100234033 is an equidigital number, since it uses as much as digits as its factorization.
13234100234033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 392319248.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 13234100234033 its reverse (33043200143231), we get a palindrome (46277300377264).
The spelling of 13234100234033 in words is "thirteen trillion, two hundred thirty-four billion, one hundred million, two hundred thirty-four thousand, thirty-three".
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