Base | Representation |
---|---|
bin | 11110000101110100010010… |
… | …101010011010101110010011 |
3 | 122100120200121121201002010011 |
4 | 132011310102222122232103 |
5 | 114321234123420313133 |
6 | 1145244403001415351 |
7 | 36606221554604320 |
oct | 3605642252325623 |
9 | 570520547632104 |
10 | 132341140401043 |
11 | 391936206a2552 |
12 | 12a1472419a557 |
13 | 58ac940055612 |
14 | 24974b99b5b47 |
15 | 104776b8d36cd |
hex | 785d12a9ab93 |
132341140401043 has 16 divisors (see below), whose sum is σ = 152908205184000. Its totient is φ = 112190932820736.
The previous prime is 132341140400993. The next prime is 132341140401049. The reversal of 132341140401043 is 340104041143231.
It is not a de Polignac number, because 132341140401043 - 217 = 132341140269971 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132341140400996 and 132341140401014.
It is not an unprimeable number, because it can be changed into a prime (132341140401049) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 63994171 + ... + 66029812.
It is an arithmetic number, because the mean of its divisors is an integer number (9556762824000).
Almost surely, 2132341140401043 is an apocalyptic number.
132341140401043 is a deficient number, since it is larger than the sum of its proper divisors (20567064782957).
132341140401043 is a wasteful number, since it uses less digits than its factorization.
132341140401043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 130025586.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 132341140401043 its reverse (340104041143231), we get a palindrome (472445181544274).
The spelling of 132341140401043 in words is "one hundred thirty-two trillion, three hundred forty-one billion, one hundred forty million, four hundred one thousand, forty-three".
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