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13235200535 = 52647040107
BaseRepresentation
bin11000101001110000…
…10010001000010111
31021011101100211221102
430110320102020113
5204101202404120
610025152140315
7645660230324
oct142470221027
937141324842
1013235200535
115681a20067
12269453769b
13132c03210b
148d7ab1b4b
15526e10d75
hex314e12217

13235200535 has 4 divisors (see below), whose sum is σ = 15882240648. Its totient is φ = 10588160424.

The previous prime is 13235200507. The next prime is 13235200577. The reversal of 13235200535 is 53500253231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13235200535 - 224 = 13218423319 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13235200498 and 13235200507.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1323520049 + ... + 1323520058.

It is an arithmetic number, because the mean of its divisors is an integer number (3970560162).

Almost surely, 213235200535 is an apocalyptic number.

13235200535 is a deficient number, since it is larger than the sum of its proper divisors (2647040113).

13235200535 is an equidigital number, since it uses as much as digits as its factorization.

13235200535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2647040112.

The product of its (nonzero) digits is 13500, while the sum is 29.

Adding to 13235200535 its reverse (53500253231), we get a palindrome (66735453766).

The spelling of 13235200535 in words is "thirteen billion, two hundred thirty-five million, two hundred thousand, five hundred thirty-five".

Divisors: 1 5 2647040107 13235200535