Base | Representation |
---|---|
bin | 11110000110000000110001… |
… | …100010110110001110000111 |
3 | 122100121222012200211120211012 |
4 | 132012000301202312032013 |
5 | 114321444101103141403 |
6 | 1145254500550432435 |
7 | 36610204653404315 |
oct | 3606006142661607 |
9 | 570558180746735 |
10 | 132354543412103 |
11 | 3919927930a0a1 |
12 | 12a1724496271b |
13 | 58b0c97a812ac |
14 | 2497dcba8b0b5 |
15 | 1047ca33e0ed8 |
hex | 7860318b6387 |
132354543412103 has 4 divisors (see below), whose sum is σ = 139320572012760. Its totient is φ = 125388514811448.
The previous prime is 132354543412067. The next prime is 132354543412151. The reversal of 132354543412103 is 301214345453231.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 132354543412103 - 28 = 132354543411847 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132354543412193) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3483014300300 + ... + 3483014300337.
It is an arithmetic number, because the mean of its divisors is an integer number (34830143003190).
Almost surely, 2132354543412103 is an apocalyptic number.
132354543412103 is a deficient number, since it is larger than the sum of its proper divisors (6966028600657).
132354543412103 is an equidigital number, since it uses as much as digits as its factorization.
132354543412103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6966028600656.
The product of its (nonzero) digits is 518400, while the sum is 41.
Adding to 132354543412103 its reverse (301214345453231), we get a palindrome (433568888865334).
The spelling of 132354543412103 in words is "one hundred thirty-two trillion, three hundred fifty-four billion, five hundred forty-three million, four hundred twelve thousand, one hundred three".
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