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132400041322 = 266200020661
BaseRepresentation
bin111101101001110101…
…0000100110101101010
3110122202012000222101011
41323103222010311222
54132123402310242
6140453532214134
712364665532243
oct1732352046552
9418665028334
10132400041322
115117240a75a
12217b060a34a
13c6401a6223
1465a0139cca
15369d8e6d17
hex1ed3a84d6a

132400041322 has 4 divisors (see below), whose sum is σ = 198600061986. Its totient is φ = 66200020660.

The previous prime is 132400041289. The next prime is 132400041349. The reversal of 132400041322 is 223140004231.

132400041322 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 132147517441 + 252523881 = 363521^2 + 15891^2 .

It is a junction number, because it is equal to n+sod(n) for n = 132400041293 and 132400041302.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33100010329 + ... + 33100010332.

Almost surely, 2132400041322 is an apocalyptic number.

132400041322 is a deficient number, since it is larger than the sum of its proper divisors (66200020664).

132400041322 is an equidigital number, since it uses as much as digits as its factorization.

132400041322 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66200020663.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 132400041322 its reverse (223140004231), we get a palindrome (355540045553).

The spelling of 132400041322 in words is "one hundred thirty-two billion, four hundred million, forty-one thousand, three hundred twenty-two".

Divisors: 1 2 66200020661 132400041322