Base | Representation |
---|---|
bin | 1100000010101011000011… |
… | …0011010101101110001010 |
3 | 1201212201220020012010200112 |
4 | 3000222300303111232022 |
5 | 3213411113144021402 |
6 | 44054221510034322 |
7 | 2534363626322414 |
oct | 300526063255612 |
9 | 51781806163615 |
10 | 13240055454602 |
11 | 4245092155889 |
12 | 159a0179489a2 |
13 | 7506bb6a4c02 |
14 | 33ab71bcb9b4 |
15 | 17e60e3e8e52 |
hex | c0ab0cd5b8a |
13240055454602 has 4 divisors (see below), whose sum is σ = 19860083181906. Its totient is φ = 6620027727300.
The previous prime is 13240055454583. The next prime is 13240055454623. The reversal of 13240055454602 is 20645455004231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11729248190401 + 1510807264201 = 3424799^2 + 1229149^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 13240055454602.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3310013863649 + ... + 3310013863652.
Almost surely, 213240055454602 is an apocalyptic number.
13240055454602 is a deficient number, since it is larger than the sum of its proper divisors (6620027727304).
13240055454602 is an equidigital number, since it uses as much as digits as its factorization.
13240055454602 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6620027727303.
The product of its (nonzero) digits is 576000, while the sum is 41.
The spelling of 13240055454602 in words is "thirteen trillion, two hundred forty billion, fifty-five million, four hundred fifty-four thousand, six hundred two".
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