132401411203035 has 16 divisors (see below), whose sum is σ = 228137816227104. Its totient is φ = 65182233207552.

The previous prime is 132401411203027. The next prime is 132401411203067. The reversal of 132401411203035 is 530302114104231.

It is not a de Polignac number, because 132401411203035 - 2³ = 132401411203027 is a prime.

It is a super-2 number, since 2×132401411203035² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132401411202993 and 132401411203011.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 339490797762 + ... + 339490798151.

It is an arithmetic number, because the mean of its divisors is an integer number (14258613514194).

Almost surely, 2^{132401411203035} is an apocalyptic number.

132401411203035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

132401411203035 is a deficient number, since it is larger than the sum of its proper divisors (95736405024069).

132401411203035 is a wasteful number, since it uses less digits than its factorization.

132401411203035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 678981595934.

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 132401411203035 its reverse (530302114104231), we get a palindrome (662703525307266).

The spelling of 132401411203035 in words is "one hundred thirty-two trillion, four hundred one billion, four hundred eleven million, two hundred three thousand, thirty-five".