Base | Representation |
---|---|
bin | 111101101001110111… |
… | …1010110010000111111 |
3 | 110122202021122012021002 |
4 | 1323103233112100333 |
5 | 4132124231022143 |
6 | 140454022000515 |
7 | 12365013346553 |
oct | 1732357262077 |
9 | 418667565232 |
10 | 132401423423 |
11 | 51173174095 |
12 | 217b0b7613b |
13 | c64056b339 |
14 | 65a03b9863 |
15 | 369dabb5b8 |
hex | 1ed3bd643f |
132401423423 has 4 divisors (see below), whose sum is σ = 132405916608. Its totient is φ = 132396930240.
The previous prime is 132401423381. The next prime is 132401423477. The reversal of 132401423423 is 324324104231.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 324324104231 = 433 ⋅749016407.
It is a cyclic number.
It is not a de Polignac number, because 132401423423 - 210 = 132401422399 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132401423923) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2202098 + ... + 2261423.
It is an arithmetic number, because the mean of its divisors is an integer number (33101479152).
Almost surely, 2132401423423 is an apocalyptic number.
132401423423 is a deficient number, since it is larger than the sum of its proper divisors (4493185).
132401423423 is an equidigital number, since it uses as much as digits as its factorization.
132401423423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4493184.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 132401423423 its reverse (324324104231), we get a palindrome (456725527654).
The spelling of 132401423423 in words is "one hundred thirty-two billion, four hundred one million, four hundred twenty-three thousand, four hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •