Search a number
-
+
132405035197 = 196968686063
BaseRepresentation
bin111101101001111110…
…1001000000010111101
3110122202112102200200111
41323103331020002331
54132131142111242
6140454231230021
712365056141531
oct1732375100275
9418675380614
10132405035197
1151175210726
12217b2218311
13c641234296
1465a0a79bc1
15369e081817
hex1ed3f480bd

132405035197 has 4 divisors (see below), whose sum is σ = 139373721280. Its totient is φ = 125436349116.

The previous prime is 132405035123. The next prime is 132405035251. The reversal of 132405035197 is 791530504231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132405035197 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132405035297) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3484343013 + ... + 3484343050.

It is an arithmetic number, because the mean of its divisors is an integer number (34843430320).

Almost surely, 2132405035197 is an apocalyptic number.

It is an amenable number.

132405035197 is a deficient number, since it is larger than the sum of its proper divisors (6968686083).

132405035197 is an equidigital number, since it uses as much as digits as its factorization.

132405035197 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6968686082.

The product of its (nonzero) digits is 113400, while the sum is 40.

The spelling of 132405035197 in words is "one hundred thirty-two billion, four hundred five million, thirty-five thousand, one hundred ninety-seven".

Divisors: 1 19 6968686063 132405035197