Base | Representation |
---|---|
bin | 11110000110110100101110… |
… | …001111010110100111011011 |
3 | 122100211022012001010010120110 |
4 | 132012310232033112213123 |
5 | 114323402320032420430 |
6 | 1145340243515055403 |
7 | 36614221141251336 |
oct | 3606645617264733 |
9 | 570738161103513 |
10 | 132410322545115 |
11 | 3920a9a216832a |
12 | 12a26011141563 |
13 | 58b6316c07844 |
14 | 249a99db3561d |
15 | 104946a2e17b0 |
hex | 786d2e3d69db |
132410322545115 has 64 divisors (see below), whose sum is σ = 214598194836480. Its totient is φ = 69706471833600.
The previous prime is 132410322545093. The next prime is 132410322545159. The reversal of 132410322545115 is 511545223014231.
It is not a de Polignac number, because 132410322545115 - 222 = 132410318350811 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 11865781906 + ... + 11865793064.
It is an arithmetic number, because the mean of its divisors is an integer number (3353096794320).
Almost surely, 2132410322545115 is an apocalyptic number.
132410322545115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
132410322545115 is a deficient number, since it is larger than the sum of its proper divisors (82187872291365).
132410322545115 is a wasteful number, since it uses less digits than its factorization.
132410322545115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18804.
The product of its (nonzero) digits is 144000, while the sum is 39.
Adding to 132410322545115 its reverse (511545223014231), we get a palindrome (643955545559346).
The spelling of 132410322545115 in words is "one hundred thirty-two trillion, four hundred ten billion, three hundred twenty-two million, five hundred forty-five thousand, one hundred fifteen".
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