Base | Representation |
---|---|
bin | 10011010001001011011… |
… | …010001110010101000100 |
3 | 11200120202212011002120111 |
4 | 103101023122032111010 |
5 | 133143241430432204 |
6 | 2452142353442404 |
7 | 164443543404400 |
oct | 23211332162504 |
9 | 4616685132514 |
10 | 1324115092804 |
11 | 4706104a5359 |
12 | 194757570404 |
13 | 97b2c1bcc1a |
14 | 481321c4100 |
15 | 2469b09cd04 |
hex | 1344b68e544 |
1324115092804 has 27 divisors (see below), whose sum is σ = 2695552805757. Its totient is φ = 567470992704.
The previous prime is 1324115092691. The next prime is 1324115092831. The reversal of 1324115092804 is 4082905114231.
The square root of 1324115092804 is 1150702.
It is a perfect power (a square), and thus also a powerful number.
It can be written as a sum of positive squares in only one way, i.e., 11605752900 + 1312509339904 = 107730^2 + 1145648^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 8 ways as a sum of consecutive naturals, for example, 16068732 + ... + 16150924.
Almost surely, 21324115092804 is an apocalyptic number.
1324115092804 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
1324115092804 is the 1150702-nd square number.
It is an amenable number.
1324115092804 is an abundant number, since it is smaller than the sum of its proper divisors (1371437712953).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1324115092804 is an frugal number, since it uses more digits than its factorization.
1324115092804 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 164404 (or 82202 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 40.
The spelling of 1324115092804 in words is "one trillion, three hundred twenty-four billion, one hundred fifteen million, ninety-two thousand, eight hundred four".
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