Base | Representation |
---|---|
bin | 11110000110110110110000… |
… | …010010001010100111000111 |
3 | 122100211111211002111210200112 |
4 | 132012312300102022213013 |
5 | 114323421302101223310 |
6 | 1145341244214103235 |
7 | 36614326203114362 |
oct | 3606666022124707 |
9 | 570744732453615 |
10 | 132412504320455 |
11 | 3921091177a447 |
12 | 12a2651b94ab1b |
13 | 58b65a3c27b78 |
14 | 249ab297cb0d9 |
15 | 1049546b0d705 |
hex | 786db048a9c7 |
132412504320455 has 16 divisors (see below), whose sum is σ = 161732803883040. Its totient is φ = 104041352391552.
The previous prime is 132412504320403. The next prime is 132412504320557. The reversal of 132412504320455 is 554023405214231.
It is a cyclic number.
It is not a de Polignac number, because 132412504320455 - 230 = 132411430578631 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 200590784 + ... + 201249813.
It is an arithmetic number, because the mean of its divisors is an integer number (10108300242690).
Almost surely, 2132412504320455 is an apocalyptic number.
132412504320455 is a deficient number, since it is larger than the sum of its proper divisors (29320299562585).
132412504320455 is a wasteful number, since it uses less digits than its factorization.
132412504320455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 401841778.
The product of its (nonzero) digits is 576000, while the sum is 41.
Adding to 132412504320455 its reverse (554023405214231), we get a palindrome (686435909534686).
The spelling of 132412504320455 in words is "one hundred thirty-two trillion, four hundred twelve billion, five hundred four million, three hundred twenty thousand, four hundred fifty-five".
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