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13241332153 = 71891618879
BaseRepresentation
bin11000101010011111…
…01011000110111001
31021011210220100221101
430111033223012321
5204104240112103
610025531411401
7646063315630
oct142517530671
937153810841
1013241332153
115685428915
1226965b3b61
13133039acaa
148d882a517
15527722a1d
hex3153eb1b9

13241332153 has 4 divisors (see below), whose sum is σ = 15132951040. Its totient is φ = 11349713268.

The previous prime is 13241332129. The next prime is 13241332189. The reversal of 13241332153 is 35123314231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13241332153 - 221 = 13239235001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13241332193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 945809433 + ... + 945809446.

It is an arithmetic number, because the mean of its divisors is an integer number (3783237760).

Almost surely, 213241332153 is an apocalyptic number.

It is an amenable number.

13241332153 is a deficient number, since it is larger than the sum of its proper divisors (1891618887).

13241332153 is an equidigital number, since it uses as much as digits as its factorization.

13241332153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1891618886.

The product of its digits is 6480, while the sum is 28.

Adding to 13241332153 its reverse (35123314231), we get a palindrome (48364646384).

The spelling of 13241332153 in words is "thirteen billion, two hundred forty-one million, three hundred thirty-two thousand, one hundred fifty-three".

Divisors: 1 7 1891618879 13241332153