13241414131 has 4 divisors (see below), whose sum is σ = 14445179064. Its totient is φ = 12037649200.

The previous prime is 13241414117. The next prime is 13241414141. The reversal of 13241414131 is 13141414231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13241414131 - 2¹⁷ = 13241283059 is a prime.

It is a super-2 number, since 2×13241414131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13241414096 and 13241414105.

It is not an unprimeable number, because it can be changed into a prime (13241414141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 601882450 + ... + 601882471.

It is an arithmetic number, because the mean of its divisors is an integer number (3611294766).

Almost surely, 2^13241414131 is an apocalyptic number.

13241414131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13241414131 is a deficient number, since it is larger than the sum of its proper divisors (1203764933).

13241414131 is a wasteful number, since it uses less digits than its factorization.

13241414131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1203764932.

The product of its digits is 1152, while the sum is 25.

Adding to 13241414131 its reverse (13141414231), we get a palindrome (26382828362).

The spelling of 13241414131 in words is "thirteen billion, two hundred forty-one million, four hundred fourteen thousand, one hundred thirty-one".