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13241501340035 = 56091434789077
BaseRepresentation
bin1100000010110000011011…
…1110111101000110000011
31201212212121222212201121212
43000230012332331012003
53213422043320340120
644055021200240335
72534444514205013
oct300540676750603
951785558781555
1013241501340035
114245764334a21
12159a3600100ab
1375088c0cb017
1433ac6bc45c43
1517e6963046c5
hexc0b06fbd183

13241501340035 has 8 divisors (see below), whose sum is σ = 15892410379056. Its totient is φ = 10591461891360.

The previous prime is 13241501340019. The next prime is 13241501340203. The reversal of 13241501340035 is 53004310514231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13241501340035 - 24 = 13241501340019 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13241501339983 and 13241501340010.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 217364084 + ... + 217424993.

It is an arithmetic number, because the mean of its divisors is an integer number (1986551297382).

Almost surely, 213241501340035 is an apocalyptic number.

13241501340035 is a deficient number, since it is larger than the sum of its proper divisors (2650909039021).

13241501340035 is an equidigital number, since it uses as much as digits as its factorization.

13241501340035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 434795173.

The product of its (nonzero) digits is 21600, while the sum is 32.

Adding to 13241501340035 its reverse (53004310514231), we get a palindrome (66245811854266).

The spelling of 13241501340035 in words is "thirteen trillion, two hundred forty-one billion, five hundred one million, three hundred forty thousand, thirty-five".

Divisors: 1 5 6091 30455 434789077 2173945385 2648300268007 13241501340035