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132418574341 = 1013913060319
BaseRepresentation
bin111101101010011000…
…0110001100000000101
3110122210110220112220021
41323110300301200011
54132143123334331
6140455433335141
712365312211334
oct1732460614005
9418713815807
10132418574341
11511819188a9
12217b68674b1
13c643c94a01
1465a27a1d1b
1536a0358211
hex1ed4c31805

132418574341 has 4 divisors (see below), whose sum is σ = 132431644800. Its totient is φ = 132405503884.

The previous prime is 132418574339. The next prime is 132418574357. The reversal of 132418574341 is 143475814231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132418574341 - 21 = 132418574339 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132418274341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6520021 + ... + 6540298.

It is an arithmetic number, because the mean of its divisors is an integer number (33107911200).

Almost surely, 2132418574341 is an apocalyptic number.

It is an amenable number.

132418574341 is a deficient number, since it is larger than the sum of its proper divisors (13070459).

132418574341 is a wasteful number, since it uses less digits than its factorization.

132418574341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13070458.

The product of its digits is 322560, while the sum is 43.

The spelling of 132418574341 in words is "one hundred thirty-two billion, four hundred eighteen million, five hundred seventy-four thousand, three hundred forty-one".

Divisors: 1 10139 13060319 132418574341