Base | Representation |
---|---|
bin | 11110000110111101111100… |
… | …011010111101001011000001 |
3 | 122100212020202002201110211111 |
4 | 132012331330122331023001 |
5 | 114324033104340102230 |
6 | 1145345002224443321 |
7 | 36615021412410634 |
oct | 3606757432751301 |
9 | 570766662643744 |
10 | 132420224144065 |
11 | 39214113383160 |
12 | 12a27b15179541 |
13 | 58b72343c1230 |
14 | 249b25cba1c1b |
15 | 104984971392a |
hex | 786f7c6bd2c1 |
132420224144065 has 64 divisors (see below), whose sum is σ = 187076549721600. Its totient is φ = 88710962227200.
The previous prime is 132420224144057. The next prime is 132420224144069. The reversal of 132420224144065 is 560441422024231.
It is not a de Polignac number, because 132420224144065 - 23 = 132420224144057 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132420224144069) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3351457660 + ... + 3351497170.
It is an arithmetic number, because the mean of its divisors is an integer number (2923071089400).
Almost surely, 2132420224144065 is an apocalyptic number.
It is an amenable number.
132420224144065 is a deficient number, since it is larger than the sum of its proper divisors (54656325577535).
132420224144065 is a wasteful number, since it uses less digits than its factorization.
132420224144065 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 49258.
The product of its (nonzero) digits is 368640, while the sum is 40.
Adding to 132420224144065 its reverse (560441422024231), we get a palindrome (692861646168296).
The spelling of 132420224144065 in words is "one hundred thirty-two trillion, four hundred twenty billion, two hundred twenty-four million, one hundred forty-four thousand, sixty-five".
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