Base | Representation |
---|---|
bin | 11000101010101001… |
… | …01011101000101001 |
3 | 1021011220101001212120 |
4 | 30111110223220221 |
5 | 204110104120113 |
6 | 10030015501453 |
7 | 646110424362 |
oct | 142524535051 |
9 | 37156331776 |
10 | 13242645033 |
11 | 5686145242 |
12 | 2696b27889 |
13 | 133073a747 |
14 | 8d8a8cb69 |
15 | 5278d1a23 |
hex | 31552ba29 |
13242645033 has 4 divisors (see below), whose sum is σ = 17656860048. Its totient is φ = 8828430020.
The previous prime is 13242645019. The next prime is 13242645041. The reversal of 13242645033 is 33054624231.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13242645033 - 212 = 13242640937 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13242644985 and 13242645003.
It is not an unprimeable number, because it can be changed into a prime (13242645043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2207107503 + ... + 2207107508.
It is an arithmetic number, because the mean of its divisors is an integer number (4414215012).
Almost surely, 213242645033 is an apocalyptic number.
It is an amenable number.
13242645033 is a deficient number, since it is larger than the sum of its proper divisors (4414215015).
13242645033 is an equidigital number, since it uses as much as digits as its factorization.
13242645033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4414215014.
The product of its (nonzero) digits is 51840, while the sum is 33.
The spelling of 13242645033 in words is "thirteen billion, two hundred forty-two million, six hundred forty-five thousand, thirty-three".
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