132430046014335 has 8 divisors (see below), whose sum is σ = 211888073622960. Its totient is φ = 70629357874304.

The previous prime is 132430046014313. The next prime is 132430046014339. The reversal of 132430046014335 is 533410640034231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132430046014335 - 2⁹ = 132430046013823 is a prime.

It is a super-3 number, since 3×132430046014335³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132430046014293 and 132430046014302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132430046014339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4414334867130 + ... + 4414334867159.

It is an arithmetic number, because the mean of its divisors is an integer number (26486009202870).

Almost surely, 2^{132430046014335} is an apocalyptic number.

132430046014335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

132430046014335 is a deficient number, since it is larger than the sum of its proper divisors (79458027608625).

132430046014335 is an equidigital number, since it uses as much as digits as its factorization.

132430046014335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8828669734297.

The product of its (nonzero) digits is 311040, while the sum is 39.

Adding to 132430046014335 its reverse (533410640034231), we get a palindrome (665840686048566).

The spelling of 132430046014335 in words is "one hundred thirty-two trillion, four hundred thirty billion, forty-six million, fourteen thousand, three hundred thirty-five".