Base | Representation |
---|---|
bin | 11110000111000111001001… |
… | …010111100000110000000011 |
3 | 122100220012020201100001102220 |
4 | 132013013021113200300003 |
5 | 114324213323341141233 |
6 | 1145353314514142123 |
7 | 36615521312444415 |
oct | 3607071127406003 |
9 | 570805221301386 |
10 | 132430105021443 |
11 | 39218323925619 |
12 | 12a29a12281943 |
13 | 58b814a500c38 |
14 | 249b9191969b5 |
15 | 1049c26de0eb3 |
hex | 7871c95e0c03 |
132430105021443 has 32 divisors (see below), whose sum is σ = 185201446766400. Its totient is φ = 84057857888256.
The previous prime is 132430105021433. The next prime is 132430105021561. The reversal of 132430105021443 is 344120501034231.
It is not a de Polignac number, because 132430105021443 - 210 = 132430105020419 is a prime.
It is a super-3 number, since 3×1324301050214433 (a number of 43 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (132430105021433) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 29730721 + ... + 33893597.
It is an arithmetic number, because the mean of its divisors is an integer number (5787545211450).
Almost surely, 2132430105021443 is an apocalyptic number.
132430105021443 is a deficient number, since it is larger than the sum of its proper divisors (52771341744957).
132430105021443 is a wasteful number, since it uses less digits than its factorization.
132430105021443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4167991.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 132430105021443 its reverse (344120501034231), we get a palindrome (476550606055674).
The spelling of 132430105021443 in words is "one hundred thirty-two trillion, four hundred thirty billion, one hundred five million, twenty-one thousand, four hundred forty-three".
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