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1324310434143 = 3796844781637
BaseRepresentation
bin10011010001010111000…
…011011001000101011111
311200121021110201110111220
4103101113003121011133
5133144141432343033
62452214012344423
7164451434646564
oct23212703310537
94617243643456
101324310434143
11470700796184
121947b0a75113
1397b60805908
144815011286b
15246ad2d6bb3
hex134570d915f

1324310434143 has 16 divisors (see below), whose sum is σ = 1788146503680. Its totient is φ = 871674594336.

The previous prime is 1324310434129. The next prime is 1324310434147. The reversal of 1324310434143 is 3414340134231.

It is not a de Polignac number, because 1324310434143 - 24 = 1324310434127 is a prime.

It is a super-2 number, since 2×13243104341432 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1324310434147) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16181121 + ... + 16262757.

It is an arithmetic number, because the mean of its divisors is an integer number (111759156480).

Almost surely, 21324310434143 is an apocalyptic number.

1324310434143 is a deficient number, since it is larger than the sum of its proper divisors (463836069537).

1324310434143 is an equidigital number, since it uses as much as digits as its factorization.

1324310434143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 150166.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 1324310434143 its reverse (3414340134231), we get a palindrome (4738650568374).

The spelling of 1324310434143 in words is "one trillion, three hundred twenty-four billion, three hundred ten million, four hundred thirty-four thousand, one hundred forty-three".

Divisors: 1 3 79 237 68447 81637 205341 244911 5407313 6449323 16221939 19347969 5587807739 16763423217 441436811381 1324310434143