Base | Representation |
---|---|
bin | 10011010001010111110… |
… | …101011011110100100111 |
3 | 11200121022101101221120212 |
4 | 103101113311123310213 |
5 | 133144203312140201 |
6 | 2452215201450035 |
7 | 164451654314636 |
oct | 23212765336447 |
9 | 4617271357525 |
10 | 1324323552551 |
11 | 47070813623a |
12 | 1947b534091b |
13 | 97b6344999c |
14 | 48151b6951d |
15 | 246ae528abb |
hex | 13457d5bd27 |
1324323552551 has 16 divisors (see below), whose sum is σ = 1340405310720. Its totient is φ = 1308356038080.
The previous prime is 1324323552547. The next prime is 1324323552593. The reversal of 1324323552551 is 1552553234231.
It is a cyclic number.
It is not a de Polignac number, because 1324323552551 - 22 = 1324323552547 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1324323552499 and 1324323552508.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1324323552521) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26014715 + ... + 26065571.
It is an arithmetic number, because the mean of its divisors is an integer number (83775331920).
Almost surely, 21324323552551 is an apocalyptic number.
1324323552551 is a deficient number, since it is larger than the sum of its proper divisors (16081758169).
1324323552551 is a wasteful number, since it uses less digits than its factorization.
1324323552551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51974.
The product of its digits is 540000, while the sum is 41.
Adding to 1324323552551 its reverse (1552553234231), we get a palindrome (2876876786782).
The spelling of 1324323552551 in words is "one trillion, three hundred twenty-four billion, three hundred twenty-three million, five hundred fifty-two thousand, five hundred fifty-one".
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