13243244042341 has 4 divisors (see below), whose sum is σ = 13243302464832. Its totient is φ = 13243185619852.

The previous prime is 13243244042323. The next prime is 13243244042393. The reversal of 13243244042341 is 14324044234231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13243244042341 - 2¹¹ = 13243244040293 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13243244042341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13243244048341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28869895 + ... + 29325028.

It is an arithmetic number, because the mean of its divisors is an integer number (3310825616208).

Almost surely, 2^{13243244042341} is an apocalyptic number.

It is an amenable number.

13243244042341 is a deficient number, since it is larger than the sum of its proper divisors (58422491).

13243244042341 is an equidigital number, since it uses as much as digits as its factorization.

13243244042341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58422490.

The product of its (nonzero) digits is 221184, while the sum is 37.

Adding to 13243244042341 its reverse (14324044234231), we get a palindrome (27567288276572).

The spelling of 13243244042341 in words is "thirteen trillion, two hundred forty-three billion, two hundred forty-four million, forty-two thousand, three hundred forty-one".