13243244143301 has 4 divisors (see below), whose sum is σ = 13243251437004. Its totient is φ = 13243236849600.

The previous prime is 13243244143277. The next prime is 13243244143351. The reversal of 13243244143301 is 10334144234231.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 8119137348100 + 5124106795201 = 2849410^2 + 2263649^2 .

It is a cyclic number.

It is not a de Polignac number, because 13243244143301 - 2⁴² = 8845197632197 is a prime.

It is a super-3 number, since 3×13243244143301³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13243244143351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1467581 + ... + 5351661.

It is an arithmetic number, because the mean of its divisors is an integer number (3310812859251).

Almost surely, 2^{13243244143301} is an apocalyptic number.

It is an amenable number.

13243244143301 is a deficient number, since it is larger than the sum of its proper divisors (7293703).

13243244143301 is an equidigital number, since it uses as much as digits as its factorization.

13243244143301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7293702.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 13243244143301 its reverse (10334144234231), we get a palindrome (23577388377532).

The spelling of 13243244143301 in words is "thirteen trillion, two hundred forty-three billion, two hundred forty-four million, one hundred forty-three thousand, three hundred one".