Base | Representation |
---|---|
bin | 111101101010110100… |
… | …1000000001000000111 |
3 | 110122211111122102100002 |
4 | 1323111221000020013 |
5 | 4132210412024221 |
6 | 140501121311515 |
7 | 12365551412114 |
oct | 1732551001007 |
9 | 418744572302 |
10 | 132433314311 |
11 | 5118a1761a1 |
12 | 217bb79559b |
13 | c647055b9c |
14 | 65a471b90b |
15 | 36a17ba80b |
hex | 1ed5a40207 |
132433314311 has 4 divisors (see below), whose sum is σ = 132444838752. Its totient is φ = 132421789872.
The previous prime is 132433314289. The next prime is 132433314331. The reversal of 132433314311 is 113413334231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132433314311 - 234 = 115253445127 is a prime.
It is a super-2 number, since 2×1324333143112 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132433314331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5744966 + ... + 5767971.
It is an arithmetic number, because the mean of its divisors is an integer number (33111209688).
Almost surely, 2132433314311 is an apocalyptic number.
132433314311 is a deficient number, since it is larger than the sum of its proper divisors (11524441).
132433314311 is a wasteful number, since it uses less digits than its factorization.
132433314311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11524440.
The product of its digits is 7776, while the sum is 29.
Adding to 132433314311 its reverse (113413334231), we get a palindrome (245846648542).
The spelling of 132433314311 in words is "one hundred thirty-two billion, four hundred thirty-three million, three hundred fourteen thousand, three hundred eleven".
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