13244000005 has 4 divisors (see below), whose sum is σ = 15892800012. Its totient is φ = 10595200000.

The previous prime is 13243999997. The next prime is 13244000041. The reversal of 13244000005 is 50000044231.

13244000005 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7048106209 + 6195893796 = 83953^2 + 78714^2 .

It is not a de Polignac number, because 13244000005 - 2³ = 13243999997 is a prime.

It is a super-3 number, since 3×13244000005³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1324399996 + ... + 1324400005.

It is an arithmetic number, because the mean of its divisors is an integer number (3973200003).

Almost surely, 2^13244000005 is an apocalyptic number.

It is an amenable number.

13244000005 is a deficient number, since it is larger than the sum of its proper divisors (2648800007).

13244000005 is an equidigital number, since it uses as much as digits as its factorization.

13244000005 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2648800006.

The product of its (nonzero) digits is 480, while the sum is 19.

Adding to 13244000005 its reverse (50000044231), we get a palindrome (63244044236).

The spelling of 13244000005 in words is "thirteen billion, two hundred forty-four million, five", and thus it is an aban number.