Base | Representation |
---|---|
bin | 11000101010110100… |
… | …00000001110100101 |
3 | 1021011222222221112202 |
4 | 30111122000032211 |
5 | 204110433240401 |
6 | 10030105424245 |
7 | 646125324545 |
oct | 142532001645 |
9 | 37158887482 |
10 | 13244040101 |
11 | 5686a08396 |
12 | 269749b085 |
13 | 1330b08726 |
14 | 8d8d33325 |
15 | 527aaa06b |
hex | 3156803a5 |
13244040101 has 4 divisors (see below), whose sum is σ = 13249818252. Its totient is φ = 13238261952.
The previous prime is 13244040091. The next prime is 13244040107. The reversal of 13244040101 is 10104044231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 5424175201 + 7819864900 = 73649^2 + 88430^2 .
It is a cyclic number.
It is not a de Polignac number, because 13244040101 - 218 = 13243777957 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13244040107) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2885636 + ... + 2890221.
It is an arithmetic number, because the mean of its divisors is an integer number (3312454563).
Almost surely, 213244040101 is an apocalyptic number.
It is an amenable number.
13244040101 is a deficient number, since it is larger than the sum of its proper divisors (5778151).
13244040101 is an equidigital number, since it uses as much as digits as its factorization.
13244040101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5778150.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 13244040101 its reverse (10104044231), we get a palindrome (23348084332).
The spelling of 13244040101 in words is "thirteen billion, two hundred forty-four million, forty thousand, one hundred one".
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