132444403113335 has 4 divisors (see below), whose sum is σ = 158933283736008. Its totient is φ = 105955522490664.

The previous prime is 132444403113329. The next prime is 132444403113353. The reversal of 132444403113335 is 533311304444231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132444403113335 - 2⁶ = 132444403113271 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132444403113292 and 132444403113301.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13244440311329 + ... + 13244440311338.

It is an arithmetic number, because the mean of its divisors is an integer number (39733320934002).

Almost surely, 2^{132444403113335} is an apocalyptic number.

132444403113335 is a deficient number, since it is larger than the sum of its proper divisors (26488880622673).

132444403113335 is an equidigital number, since it uses as much as digits as its factorization.

132444403113335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26488880622672.

The product of its (nonzero) digits is 622080, while the sum is 41.

Adding to 132444403113335 its reverse (533311304444231), we get a palindrome (665755707557566).

The spelling of 132444403113335 in words is "one hundred thirty-two trillion, four hundred forty-four billion, four hundred three million, one hundred thirteen thousand, three hundred thirty-five".